Simon: Unknown column 'folder_name.visible' in 'field list'

Beitrag lesen

Der Code sieht so aus:

$var_visible = "1";
         $var_status = "visible";

$sql = "SELECT folder_name.id FROM folder_name WHERE folder_name.visible = ".$var_visible." AND folder_name.status = ".$var_status."";
         echo $sql;
         $dir = mysql_query($sql);
         echo $dir;

Gruß ... der Simon