XSLT 1.0 zusammenführen mehrerer Knoten

[ThomasM]

Hallo Julian,

war gerade am ersten XML-Code dran, als Du wieder mal die Perspektive gewechselt hast.

Probiere es so:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>

  <xsl:key name="header_text" match="HeaderText" use="Qualifier"/>
  <xsl:key name="line_text" match="LineText" use="Qualifier"/>

  <xsl:template match="@* | node()">
    <xsl:copy>
      <xsl:apply-templates select="@* | node()"/>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="HeaderText">
    <xsl:for-each select=".[generate-id() = generate-id(key('header_text', Qualifier)[1])]">
      <HeaderText>
        <xsl:copy-of select="Qualifier"/>
        <Text>
          <xsl:for-each select="key('header_text', Qualifier)">
            <xsl:value-of select="Text"/>
            <xsl:if test="position() != last()">
              <xsl:text> </xsl:text>
            </xsl:if>
          </xsl:for-each>
        </Text>
      </HeaderText>
    </xsl:for-each>
  </xsl:template>

  <xsl:template match="LineText">
    <xsl:for-each select=".[generate-id() = generate-id(key('line_text', Qualifier)[1])]">
      <LineText>
        <xsl:copy-of select="Qualifier"/>
        <Text>
          <xsl:for-each select="key('line_text', Qualifier)">
            <xsl:value-of select="Text"/>
            <xsl:if test="position() != last()">
              <xsl:text> </xsl:text>
            </xsl:if>
          </xsl:for-each>
        </Text>
      </LineText>
    </xsl:for-each>
  </xsl:template>

</xsl:stylesheet>

Grüße,
Thomas